Aug. 25 (UPI) — Milwaukee Bucks celebrity Giannis Antetokounmpo was named the 2019-20 NBA Defensive Player of the Year on Tuesday.
Antetokounmpo, 25, beat out Los Angeles Lakers star Anthony Davis and Utah Jazz large man Rudy Gobert to earn the award for the first time in his seven-year profession. He captured the award in a landslide, receiving 75 first-place votes and incomes 432 whole factors.
The “Greek Freak” turns into the second participant in Bucks historical past to win the award, becoming a member of two-time winner Sidney Moncrief (1983-84).
Davis completed second with 14 first-place votes (200 factors) and Gobert — who received the award in every of the previous two seasons — got here in third with six first-place votes (187 factors).
Ben Simmons (fourth), Bam Adebayo (fifth), Patrick Beverley (sixth), Marcus Good (seventh), Andre Drummond (eighth), Kawhi Leonard (ninth), Brook Lopez (10th), Hassan Whiteside (11th) and Jarrett Allen (12th) additionally obtained votes.
Antetokounmpo, a two-time NBA All-Defensive choice, anchored the finest defensive workforce in the NBA in the Bucks. He averaged 13.6 rebounds, one block and one steal in 30.four minutes per sport this season.
Antetokounmpo — the reigning NBA Most Worthwhile Player — additionally is taken into account the favourite to win the league’s MVP award this 12 months. He would be a part of Michael Jordan (1987-88) and Hakeem Olajuwon (1993-94) as the solely gamers in league historical past to win MVP and DPOY in the similar season.